Starting with a sample of pure {}^{66}Cu,frac | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given that $\frac{7}{8}$ of the sample of ${}^{66}Cu$ decays in $15 \ minutes$.The fraction of the sample remaining undecayed is $N = 1 - \frac{7}

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(D) Given that $\frac{7}{8}$ of the sample of ${}^{66}Cu$ decays in $15 \ minutes$.The fraction of the sample remaining undecayed is $N = 1 - \frac{7}{8} = \frac{1}{8}$.We know that the remaining amount $N$ after $n$ half-lives is given by $N = \left(\frac{1}{2}\right)^n$.Since $\frac{1}{8} = \left(\frac{1}{2}\right)^3$,the number of half-lives $n$ is $3$.The relationship between time $t$,number of half-lives $n$,and half-life $T$ is $n = \frac{t}{T}$.Substituting the values,$3 = \frac{15}{T}$.Therefore,the half-life $T = \frac{15}{3} = 5 \ minutes$.

Starting with a sample of pure ${}^{66}Cu$,$\frac{7}{8}$ of it decays into $Zn$ in $15 \ minutes$. The corresponding half-life is .......... $minutes$.

Similar Questions

$A$ radioactive material has a half-life of $10$ days. What fraction of the material would remain after $30$ days?

The count rate of $10\,g$ of radioactive material was measured at different times and this has been shown in the figure. The half-life of the material and the total counts (approximately) in the first half-life period,respectively,are:

If $20 \, g$ of a radioactive substance reduces to $10 \, g$ due to radioactive decay in $4 \, minutes$, then in what time will $80 \, g$ of the same substance reduce to $10 \, g$?

$A$ radioactive material decays by simultaneous emission of two particles with respective half-lives $1620$ years and $810$ years. The time (in years) after which one-fourth of the material remains is:

The initial activity of a radioactive element is $1600$. After $t = 8 \, s$,the activity becomes $100$. What is the activity at $t = 6 \, s$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module